Since there have the right to be <-ℓ, ℓ> orientations and since the orbital form f has actually ℓ = 3, we should have actually 7 possible orientations v 2 spins, therefore $7 imes 2 = 14$, for this reason I thought the correct answer to be D (14).

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However, I obtained it wrong and the correct answer is marked as C (2). Is it an error in the test, or am I missing something?

You"re correct that there space seven feasible spatial orientations because that an f-type orbital, and hence seven feasible orbitals in one f-type sub-shell. However, the inquiry specifically asks for the maximum number of electrons in one such orbital, and also

*any*solitary atomic orbital, regardless of the sub-shell kind specified by $l$, deserve to only organize two electrons. This is by virtue that the Pauli exclusion principle. Fourteen would be the maximum variety of electrons throughout an whole f-type sub-shell, yet the question just asks around one orbital.

The inquiry specifically ask that no.of electron an orbit of f subshell deserve to hold.... Together we understand that f subshell contain 7 orbital and also each orbital can hold maximum 2 electons so exactly answer would certainly be 2..we deserve to simply understand this by acquisition the real life example imagine the there is residence named f which consists of 7 rooms so an in similar way in this instance house is a subshell and each room is one orbital... Say thanks to you,

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