The particular heat volume the substance is calculated making use of the below formulaQ(heat) = Mc delta TQ =1560 calm(mass) 312 gdelta T (change in temperature ) = 15 cC= specific heat capacity=?by make c the subject of the formula c=Q/m delta T= 1560 cal/ 312g x 15 c = 0.33 cal/g/c (answer B)

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